Posted by Anonymous on Wednesday, March 25, 2009 at 11:43pm.
Please help!
(a^2)63
(2x)^3
(p^2q)^3
5c(2cd)^3
4y(y62z)63
(12a^5)^2b^3
6a(ab)^7
(2d^2)^6(3)^3
please and thanc u!

PreAlgebra  drwls, Thursday, March 26, 2009 at 12:50am
Learn and apply these rules for taking powers of numbers with exponents,
(x^a)^b = x^(ab) ,
(x^a*y^b)^c = x^(ac) * y^(bc)
and multiplying variables with exponents.
x^a*x^b = x^(a+b)
Here is how this works with two examples. You should do the rest yourself.
(p^2*q)^3 = p^6*q^3
6a(ab)^7 = 6a*(1)^7 * a^7 * b^7
= 6a^8 * b^7
The * symbol indicates multiplication, but could be left out
Answer This Question
Related Questions
 PreCalc  Please help me solve these two equations!! Divide and express as a ...
 Algebra......Help Quick!!  12a^3bc18a^2bc^2+6a^2c, x^2+20x+36, 12x^48x^34x^2...
 algebra  simplify 2a^+6ab^12a^b/24ab the b 12a^b the b is to the third ...
 algebra  (5c²+5cd)+(4c²d2cd6)+(cd+8)
 algebra  I need help with these please. What is the solution for 0.7x+5¡Ü1.1x8...
 algebra  simplify 2a^2 + 6ab^212a^2b^3 divided by 24ab 2a^2/24ab + 6ab^2/...
 pre alg  12a^4 b^6 c^3 / 30 a^2 b^5 c^3 is the answer 2b/5a^6 c^?
 pre calc  factor ((5a^2+12a+4)/(a^416)) / ((25a^2+20a+4)/(a^22a))
 Math  12a3b2. When a=9 b=4. Please explain steps
 Algebra  1. √(9y  196) + √196 = √49 My work: I squared all 3...
More Related Questions