Posted by Dana on Wednesday, March 25, 2009 at 11:39pm.
You're losing it in the equation.
HCl + H2O ==> H3O^+ + Cl^-
Now, HCl is the acid because you can see it has donated a proton to H2O. How do I know it donated a proton? Because on the right side of the equation, there Cl^- is by its lonesome, without the proton it had on the left side. So clearly, HCl has lost a proton. That makes HCl the acid and it makes Cl^- the conjugate base. Now, we had H2O on the left. On the right, it is H3O^+. Clearly, the H2O has gained a H^+ (accepted a proton) to become the hydronium ion. So H2O has acted as a base because it accepted a proton, the H3O^+ is the conjugate acid. And your definitions are correct.
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