I did a redox titration of NaBO3 with KMnO4. I used a .0545 M NaBO3 solution, and an average of .026 L of .01M KMnO4. I have to standardize the KMnO4 solution, does anyone know how to do this?

Write the equation and balance it.
Calculate moles NaBO3 used. That will be M x L NaBO3.
Using the coefficients in the balanced equation, convert moles NaBO3 to moles KMnO4, then,
M KMnO4 = moles KMnO4/L KMnO4.
Post your work if you get stuck.