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September 20, 2014

September 20, 2014

Posted by **John Wilson** on Wednesday, March 25, 2009 at 7:05pm.

(b-6)*(b+3)

- 9th grade -
**laarsen**, Wednesday, March 25, 2009 at 7:18pm(b-6)(b+3)

use FOIL:

b*b

b*3

-6*b

-6*3

add them together to get:

b^2 - 3b - 18

- 9th grade -
**Dora**, Friday, April 17, 2009 at 3:54pmYou distribute the first set of brackets.

When you have equations like this you should pretend there are no brackets around the first equation.

b-6 (b+3)

first you distribute b into the brackets.

(b)(b) = b^2

then b to 3

(b)(3) = 3b

then you distribute the -6 to both...

(-6)(b) = -6b

then -6 to 3...

(-6)(3) = -18

then you add them together...

b^2-3b-18

:)

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