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August 29, 2014

August 29, 2014

Posted by **Jake** on Wednesday, March 25, 2009 at 5:23pm.

(g x f)^-1

- Math -
**bobpursley**, Wednesday, March 25, 2009 at 5:32pmPlease state in words your notation

(g x f)^-1 I assume you do not mean the reciprocal of g times f.

- Math -
**Reiny**, Wednesday, March 25, 2009 at 5:36pmlet y = g x f

= (x+4)(2x-5)

y = 2x^2 + 3x - 20

so the inverse of that is

x = 2y^2 + 3y - 20

2y^2 + 3y - 20 - x = 0

which by the way is not a function

to solve for y you will have to use the quadratic formula and

y = (-3 ± √(9-8(-20-x))/4

etc.

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