Posted by Kim on Wednesday, March 25, 2009 at 2:29pm.
(2-3i)(5i) over 2+3i
= 5i(2-3i)/(2+3i)
multiply top and bottom by 2-3i
= 5i(4 - 12i + 9i^2)/(4-9i^2)
= 5i(-13 - 12i)/13
= (-65i - 60i^2)/13
= (60 - 65i)/13
or 60/13 - 5i if by standard form you mean a + bi
ok, Kim ,I messed up in the arithmetic
but, if you understand what I did, you should be able to fix it yourself.
hint: the error is from
= 5i(4 - 12i + 9i^2)/(4-9i^2) to
= 5i(-13 - 12i)/13
YOU SHOULD KNOW HOW TO DO THIS!
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