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March 28, 2017

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what's the limit as n goes to infinity of (2 + 4/n^2)^(1/3)

  • calculus - ,

    as n --> ∞ , 4/n^2 ---> 0
    so your expression becomes
    (2+0)^(1/3)
    which is the cuberoot of 2 or appr. 1.2599

  • calculus - ,

    thnx

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