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October 31, 2014

October 31, 2014

Posted by **Jessi** on Tuesday, March 24, 2009 at 12:36pm.

I know that the equation to solve for the initial velocity needs to be ((m_1+m_2)*v_f)/m_1 where m_1 is the mass of the bullet and m_2 is the mass of the block. What i don't know is how to get the final velocity in other terms so I can solve it.

- physics -
**Count Iblis**, Tuesday, March 24, 2009 at 12:51pmHow long does it take for the block to fall to the ground? You are given the height of the table....

In the time it takes for the block to fall to the ground, the block has moved 2 meters. So, you can compute the final speed for this.

- physics -
**Courtney**, Thursday, March 7, 2013 at 3:29pmFirst you have to calculate the time it takes for the block to hit the ground.

y(t)=vit+(1/2)gt^2

y(t)=1+(1/2)(-9.80)t^2

Solve for t: t=0.45s

With distance and time you can calculate velocity: d/t= 2.00/0.45= 4.44m/s

Use this velocity in calculating the initial velocity of the bullet.

Multiply the mass of the block times your velocity that you just calculated...2.30kg x 4.44m/s=10.2 now divide this number by the mass of your bullet- be sure that you have like terms.

10.2/.006kg=1702 m/s is the initial velocity of your bullet

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