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March 27, 2015

March 27, 2015

Posted by **Suz** on Tuesday, March 24, 2009 at 2:39am.

- Math -
**Damon**, Tuesday, March 24, 2009 at 5:50amInitial position of bear at C

final position of bear at D

angle CAB = 90-43 = 47

angle CBA = 90-30 = 60

therefore angle ACB = 180-47-80 = 73

sin 60/AC = sin 73/10

AC = 10 sin 60 /sin 73

do that

then

angle DAC = 43-24 = 19

angle DCA = 180 - 73 = 180-73 = 107

angle ADC = 180 -19 -107 = 54

so

sin 19/DC = sin 54 / AC

and we know AC

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