Posted by Suz on Tuesday, March 24, 2009 at 2:39am.
Initial position of bear at C
final position of bear at D
angle CAB = 90-43 = 47
angle CBA = 90-30 = 60
therefore angle ACB = 180-47-80 = 73
sin 60/AC = sin 73/10
AC = 10 sin 60 /sin 73
do that
then
angle DAC = 43-24 = 19
angle DCA = 180 - 73 = 180-73 = 107
angle ADC = 180 -19 -107 = 54
so
sin 19/DC = sin 54 / AC
and we know AC
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