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March 4, 2015

March 4, 2015

Posted by **jaz** on Monday, March 23, 2009 at 10:01am.

Tossing 2, then 2.

Tossing red, then white, then yellow.

- Math - probability -
**Writeacher**, Monday, March 23, 2009 at 10:05amassistance needed

- Independent and dependent events -
**jaz**, Monday, March 23, 2009 at 10:14amcan you show me how to start

- Independent and dependent events -
**Reiny**, Monday, March 23, 2009 at 10:23amProb(2, then another 2) = 2/6 * 2/6 = 1/9

Prob(red,white,yellow) = 4/6 * 1/6 * 1/6 = 1/54

- Independent and dependent events -
**jaz**, Monday, March 23, 2009 at 10:26amthese are the answers for them

- Independent and dependent events -
**Dr Russ**, Monday, March 23, 2009 at 11:57amFor the first one there are 6 possible numbers, two of which are 2. So the probability of rolling a 2 is 2/6.

If these are independent then the probability of throwing another 2 is also 2/6.

The probability of the combined two events is the product of the probabilities thus

2/6*2/6 = 1/9

The same approach is taken for the coloured sides.

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