Post a New Question

Independent and dependent events

posted by on .

A six-sided-cube is labeled with the numbers 1, 2, 2, 3, 3, and 3. Four sides are colored red, one side is white, and one side is yellow. Find each probability.

Tossing 2, then 2.

Tossing red, then white, then yellow.

  • Math - probability - ,

    assistance needed

  • Independent and dependent events - ,

    can you show me how to start

  • Independent and dependent events - ,

    Prob(2, then another 2) = 2/6 * 2/6 = 1/9

    Prob(red,white,yellow) = 4/6 * 1/6 * 1/6 = 1/54

  • Independent and dependent events - ,

    these are the answers for them

  • Independent and dependent events - ,

    For the first one there are 6 possible numbers, two of which are 2. So the probability of rolling a 2 is 2/6.

    If these are independent then the probability of throwing another 2 is also 2/6.
    The probability of the combined two events is the product of the probabilities thus
    2/6*2/6 = 1/9

    The same approach is taken for the coloured sides.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question