Posted by **jaz** on Monday, March 23, 2009 at 10:01am.

A six-sided-cube is labeled with the numbers 1, 2, 2, 3, 3, and 3. Four sides are colored red, one side is white, and one side is yellow. Find each probability.

Tossing 2, then 2.

Tossing red, then white, then yellow.

- Math - probability -
**Writeacher**, Monday, March 23, 2009 at 10:05am
assistance needed

- Independent and dependent events -
**jaz**, Monday, March 23, 2009 at 10:14am
can you show me how to start

- Independent and dependent events -
**Reiny**, Monday, March 23, 2009 at 10:23am
Prob(2, then another 2) = 2/6 * 2/6 = 1/9

Prob(red,white,yellow) = 4/6 * 1/6 * 1/6 = 1/54

- Independent and dependent events -
**jaz**, Monday, March 23, 2009 at 10:26am
these are the answers for them

- Independent and dependent events -
**Dr Russ**, Monday, March 23, 2009 at 11:57am
For the first one there are 6 possible numbers, two of which are 2. So the probability of rolling a 2 is 2/6.

If these are independent then the probability of throwing another 2 is also 2/6.

The probability of the combined two events is the product of the probabilities thus

2/6*2/6 = 1/9

The same approach is taken for the coloured sides.

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