Posted by jessi on Sunday, March 22, 2009 at 11:16pm.
That's a neat problem. The falling water applies a force to the bucket that must be added to the weight to get the scale reading. The added force equals the force that the bucket applies to the water to stop its fall. The bucket reduces the momentum of the water at a rate of dM/dt * V, where V is the velocity when it hits the bucket,
V = sqrt(2gH) = 6.57 m/s.
The water flow rate dM/dt is 0.22 kg/s
Total force = (0.720)*g + 6.57*0.22 + (3.2)(0.22)*g = 7.06 + 1.45 + 6.90 N
The last term added is the weight of water already collected at t = 3.2 s
how did you get that the velocity is sqrt(2gH)?
nevermind i figured it out
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