Algebra
posted by A.W. .
Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mile per hour and train B is traveling at 88 miles per hour. Train A passes a station at 9:20 P.M. If train B passes the same station at 9:50 P.M., at what time will train B catch up with train A?

let the time be t hrs after train B passes the station.
At that moment train A will be 40 miles down the track (1/2 hour x 80 mph)
and will travel another 80t miles
when train B reaches train A, train B will have traveled 88t miles
so 88t = 40 + 80t
solve for t
add t to 9:50 pm