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Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 mile per hour and train B is traveling at 88 miles per hour. Train A passes a station at 9:20 P.M. If train B passes the same station at 9:50 P.M., at what time will train B catch up with train A?

  • Algebra -

    let the time be t hrs after train B passes the station.
    At that moment train A will be 40 miles down the track (1/2 hour x 80 mph)
    and will travel another 80t miles
    when train B reaches train A, train B will have traveled 88t miles

    so 88t = 40 + 80t
    solve for t
    add t to 9:50 pm

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