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September 18, 2014

September 18, 2014

Posted by **A.W.** on Sunday, March 22, 2009 at 9:22pm.

- Algebra -
**Reiny**, Sunday, March 22, 2009 at 9:32pmlet the time be t hrs after train B passes the station.

At that moment train A will be 40 miles down the track (1/2 hour x 80 mph)

and will travel another 80t miles

when train B reaches train A, train B will have traveled 88t miles

so 88t = 40 + 80t

solve for t

add t to 9:50 pm

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