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November 28, 2014

November 28, 2014

Posted by **TJ** on Sunday, March 22, 2009 at 6:04pm.

1. y= x squared + 2, x = negative 1, x = 1 about y = 1.

- AP Calculus -
**Reiny**, Sunday, March 22, 2009 at 10:55pmyou will get the same solid if you rotate y = x^2 + 1 about the x-axis.

then volume

= [integral] pi(y^2)dx from -1 to 1

or

= 2pi[integral](x^2+1)^2 dx from 0 to 1

= 2pi[integral](x^4 + 2x^2 + 1) dx from 0 to 1

= ...

this is quite easy to integrate and finish.

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