We are learning probability and can you please check my answer.

Question: Enrique has 3 dimes, 2 quarters, and 5 nickels in his pocket. He takes one coin from his pocket at random. What is the probability that the coin is either a dime or a nickel?

My answer is 8:10 which equals 4:5

The prob(dime or nickel) = 8/10 = 4/5

Probability is normally expressed as a fraction between 0 and 1

your wrote your answer in ratio form.
Normally odds are expressed that way.

e.g. suppose the odds in favour of some event is given as 4:5

that means the prob of that event happening is 4/9 and the prob of that event NOT happening is 5/9.

I don't know at what grade level you are studying probability, but I thought it was worth clearing up.

I guess I do know what grade level, all I had to do was look at the subject title.

To determine the probability of selecting a dime or a nickel from Enrique's pocket, we first need to find the total number of dimes and nickels he has.

Enrique has 3 dimes and 5 nickels, which add up to a total of 8 coins that are either dimes or nickels.

Now, let's calculate the total number of coins in Enrique's pocket, including all dimes, quarters, and nickels. He has 3 dimes, 2 quarters, and 5 nickels, which gives us a total of 10 coins.

To find the probability, we divide the number of favorable outcomes (coins that are either dimes or nickels) by the total number of possible outcomes (all the coins in Enrique's pocket).

The probability of selecting a dime or a nickel is given by:
Number of favorable outcomes / Total number of possible outcomes

In this case, the number of favorable outcomes is 8 (since Enrique has 8 coins that are either dimes or nickels), and the total number of possible outcomes is 10 (as he has a total of 10 coins).

Therefore, the probability of selecting a dime or a nickel can be expressed as 8/10 or simplified as 4/5.

Your answer of 4/5 is correct! Great job!