Monday

November 24, 2014

November 24, 2014

Posted by **Log** on Saturday, March 21, 2009 at 8:17pm.

r=5+2sin(theta)

- Calculus -
**Count Iblis**, Saturday, March 21, 2009 at 9:39pmYou have to integrate 1/2 r^2 from theta = 0 to 2 pi.

1/2 r^2 = 1/2 [25 + 20 sin(theta)

+ 4 sin^2(theta)]

The sin(theta) term doesn't contribute to the integral and sin^2(theta) can be replaced by 1/2 [because it would yield the same contribution as cos^2(theta) and together they are equal to 1].

So, the area is given by:

pi[25 + 2 ] = 27 pi

**Answer this Question**

**Related Questions**

Calculus - find the area of the region inside the limacon r= 8 + 4sin(theta) ...

Calculus - Find the area of the region enclosed by the given curves: y=e^6x, y=...

Calculus - Find the area of the region enclosed between y = 2sin (x) and y = ...

Calc 2: Area under the curve - Find the area of the region enclosed between y=...

Calculus - Let f(x)=x^3+3x and g(x=5x^2-x Determine the area of the region ...

Calculus - Calculate the area of the common interior of r = 2sin(theta) and r = ...

pre-calc - area of a rectangular region: a farmer wishes to create two ...

Calculus - please help! - Suppose that 0 < c < ¥ğ/2. For what value of c ...

calculus - show that the area(A) of an isosceles triangle, whose equal sides are...

calculus - the region enclosed by 2y=5xy=5 and 2y+3x=8. Decide whether to ...