Saturday

February 28, 2015

February 28, 2015

Posted by **Jul** on Saturday, March 21, 2009 at 7:48pm.

x(t)=t^2–14t–4

y(t)=t^2–14t+48

How many units of distance are covered by the point P(t) = (x(t),y(t)) between t=0, and t=11 ?

- Calculus -
**bobpursley**, Saturday, March 21, 2009 at 7:50pmdistance, or displacement? There is a pronounced difference in those.

- Calculus -
**GanonTEK**, Saturday, March 21, 2009 at 7:52pmwell to get a distance between points we use the distance formula but first we need the points themselves.

Point 1 is found by subbing t=0 in for t in x(t) and y(t)

Point 2 is found by subbing t=11 in for t

in x(t) and y(t)

I'll do point 1

x(t) = (0)^2 - 14(0) - 4 = -4

y(t) = (0)^2 - 14(0) + 48 = 48

so point 1 is (-4,48)

Hope that helps

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