Posted by sarah on Saturday, March 21, 2009 at 5:20pm.
Hi could someone please explain to me how i would use the chain rule
dy/dx = dy/du(du/dx) to solve for
y= sin(x+y)  im looking for dy/dx
i don't understand the steps
thanks

math calculus  Reiny, Saturday, March 21, 2009 at 5:52pm
let u = x + y
du/dx = 1 + dy/dx
then y = sin u
and dy/dx = cosu du/dx
= cosu (1 + dy/dx)
= cosu + dy/dxcosu
dy/dx  dy/dxcoxu = cosu
dy/dx = cosu/(1  cosu)
= cos(x+y)/( 1  cos(x+y)
personally I would bypass all that subbing and my second line would be
dy/dx = cos(x+y)(1 + dy/dx)
etc. 
math calculus  sarah, Saturday, March 21, 2009 at 9:18pm
alright, but i don't know how i would now isolate for dy/dx?