Friday

March 6, 2015

March 6, 2015

Posted by **sarah** on Saturday, March 21, 2009 at 5:20pm.

dy/dx = dy/du(du/dx) to solve for

y= sin(x+y) - im looking for dy/dx

i don't understand the steps

thanks

- math calculus -
**Reiny**, Saturday, March 21, 2009 at 5:52pmlet u = x + y

du/dx = 1 + dy/dx

then y = sin u

and dy/dx = cosu du/dx

= cosu (1 + dy/dx)

= cosu + dy/dxcosu

dy/dx - dy/dxcoxu = cosu

dy/dx = cosu/(1 - cosu)

= cos(x+y)/( 1 - cos(x+y)

personally I would bypass all that subbing and my second line would be

dy/dx = cos(x+y)(1 + dy/dx)

etc.

- math calculus -
**sarah**, Saturday, March 21, 2009 at 9:18pmalright, but i dont know how i would now isolate for dy/dx?

**Answer this Question**

**Related Questions**

calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...

calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...

calculus - Let z = ∫(e^sin(t)dt) from x to y a = x b = y I tried thinking ...

calculus - Find dz/dy and dz/dx Let z = ∫e^(sin(t))dt from x to y a = x b...

calculus - I have been asked to solve this two different ways. The first way is...

Math - Calculus Question. - hey can someone explain to me the relationship ...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

calculus - Could someone check my reasoning? thanx Find the derivative of the ...

Calculus - Use implicit differentiation to find dy/dx. e^4x = sin(x+2y). This is...

Calculus - Can anyone explain how to use the chain rule and power rule together ...