Posted by **jared** on Saturday, March 21, 2009 at 5:19pm.

I've attempted this problem a few times but I can't get the right answer. Can someone show me how I can do it?

A ship leaves the port of Miami with a bearing of 100 degrees and a speed of 15 knots. After 1 hour, the ship turns 90 degrees toward the south.

a) what is the new bearing

b) after 2 hours, maintaining the same speed, what is the bearing of the ship from the port?

- math- precalculus -
**Damon**, Saturday, March 21, 2009 at 7:30pm
Landlubber mathematicians have never been to sea :(

The direction a ship is heading is called "heading"

The direction the ship is from you is called its "bearing".

That aside:

from origin go 15 nautical miles at 90 + 10 degrees clockwise from North, or 10 degrees South of East.

Now turn 90 degrees toward South, which gives you a heading 10 degrees West of South (190 degrees heading), go 30 Nautical miles.

So my East components are:

15 cos 10 - 30 sin 10

= 9.56

And my South components are:

15 sin 10 + 30 cos 10

=32.1

So the tangent of my angle from the South axis from the origin is

tan (angle) = 9.56/32.1 = .298

so

angle east of south = 16.6 degrees

However for our bearing from the origin we want clockwise from North

180 - 16.6 = 163.4

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