Calculus
posted by Sandra on .
How do you find the critical numbers and the end points of this function:
f(x)=2x^33x^212x+5
i calculated the critical numbers as x=1 and x=2 is this right?!?!

great so far.
now find f(2) and f(1) for the y values of your critical points.
unless there is a domain given for your x's , there are no "end points" for your function. 
If by "ritical numbers" you mean where the function has a local maximum or minimum, that would be where
f'(x) = 6x^2 6x 12 = 0
x^2 x 2 = 0
(x+1)(x2) = 0
yes, 1 and 2 are correct.
f(x) has no end points or absolute maximum or minimum. It goes to + and  infinity when x does the same