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March 30, 2015

March 30, 2015

Posted by **Sandra** on Saturday, March 21, 2009 at 2:38pm.

f(x)=2x^3-3x^2-12x+5

i calculated the critical numbers as x=-1 and x=2 is this right?!?!

- Calculus -
**Reiny**, Saturday, March 21, 2009 at 2:44pmgreat so far.

now find f(2) and f(-1) for the y values of your critical points.

unless there is a domain given for your x's , there are no "end points" for your function.

- Calculus -
**drwls**, Saturday, March 21, 2009 at 2:46pmIf by "ritical numbers" you mean where the function has a local maximum or minimum, that would be where

f'(x) = 6x^2 -6x -12 = 0

x^2 -x -2 = 0

(x+1)(x-2) = 0

yes, -1 and 2 are correct.

f(x) has no end points or absolute maximum or minimum. It goes to + and - infinity when x does the same

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