Posted by **Sandra** on Saturday, March 21, 2009 at 2:38pm.

How do you find the critical numbers and the end points of this function:

f(x)=2x^3-3x^2-12x+5

i calculated the critical numbers as x=-1 and x=2 is this right?!?!

- Calculus -
**Reiny**, Saturday, March 21, 2009 at 2:44pm
great so far.

now find f(2) and f(-1) for the y values of your critical points.

unless there is a domain given for your x's , there are no "end points" for your function.

- Calculus -
**drwls**, Saturday, March 21, 2009 at 2:46pm
If by "ritical numbers" you mean where the function has a local maximum or minimum, that would be where

f'(x) = 6x^2 -6x -12 = 0

x^2 -x -2 = 0

(x+1)(x-2) = 0

yes, -1 and 2 are correct.

f(x) has no end points or absolute maximum or minimum. It goes to + and - infinity when x does the same

## Answer This Question

## Related Questions

- help please! - f(x)=x+1/x Find all critical numbers. Find where the function is ...
- Calculus - Find the critical numbers of the function g(t)=|5t-7| If you find g'(...
- critical points - (1 pt) Find all critical values for the function f(x) = 6 x^3...
- CALCULUS - 6. f(x)= 12x^5 + 30x^4 - 160x^3 +4 For this function there are four ...
- Calculus (pleas help!) - Consider the function f(x)=12x^5+60x^4−100x^3+4. ...
- calculus - Please help!! *f(x)= x(x+6)^1/2 find two x intercepts. Then show that...
- Calculus - Please check, if there is something wrong please explain what I did ...
- Calculus - Differentiate to find critical numbers and leave function in fully ...
- Math - Consider the function y = 3x5 – 25x3 + 60x + 1. Find the critical points ...
- Calculus (urgent!!) - Please answer the following questions about the function f...

More Related Questions