Posted by Madeline on Saturday, March 21, 2009 at 1:51pm.
I need help with this problem.
(Just imagine a small square with 5x1 at the top of the square, 2x on the left side of the square and in the right hand corner of the square there is a box on the top is a 3 and on the left side is a 2.) You have to figure it out the area of each shaded region in simplest form.

Math  Reiny, Saturday, March 21, 2009 at 2:06pm
since you say it is a square, its sides must be equal
so 5x1 = 2x
x = 1/3 , mmmhhh!
then you say there is a box in the corner of the square.
A box is 3dimensional, a square has 2 dimensions.
What is the "shaded" region?
Sorry, I don't follow you question, perhaps somebody else can see what you mean.

Math  Madeline, Saturday, March 21, 2009 at 2:07pm
You know how when you have a right angle in the corner... well that's what the box that has 3 on the top and 2 on the left side is.

Reiny  Madeline, Saturday, March 21, 2009 at 2:12pm
Do understand what I mean now?

Math  Reiny, Saturday, March 21, 2009 at 2:41pm
I can't reconcile the fact,since the first square must be 2/3 by 2/3, that there can be a "box" inside it with sides 3 and 2.
What part of the original square was 5x1 ?
Was it the entire length or just part of it.
Perhaps if you name the vertices with letters A, B, etc and length of sides as AB, somebody here can figure out what you mean.

Further help needed here  Math  Reiny, Saturday, March 21, 2009 at 2:51pm
anybody else follow Madeline's problem?

Math  economyst, Monday, March 23, 2009 at 10:12am
I too am lost.
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