Posted by **Henri** on Saturday, March 21, 2009 at 6:50am.

A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length.

a) Find the mechanical advantage.

Mechanical Advantage=Load/Effort

M.A.=8000N/159.155N

M.A.=50.265 (Ans.)

b) Find the velocity ratio.

Efficiency(ç)=(Mechanical Advantage)/(Velocity Ratio)

V.R.=(M.A.)/ç

V.R.=50.265/0.40

Velocity Ratio=125.66 (Ans.)

c) Find the mean pitch of thread.

V.R.=(Distance moved by effort)/(Distance moved by load)

V.R.=2ðL/(2Xpitch of thread)

2Xpitch of thread=2ðX200mm/126.66

2Xpitch of thread=1256.637/126.66

Pitch of thread=9.921/2

Pitch of thread=4.96mm (Ans.)

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