Posted by sweety on Saturday, March 21, 2009 at 6:10am.
The truck rises a distance of L sin 11, before momentarily stopping. At that point,
M g L sin 11 = (1/2) M Vo^2, where Vo is the initial velocity
Thus L = Vo^2/(2 g sin 11
For b, you will get the same answer, since M cancels out.
For (c), multiply the length required by (0.89)^2 = 0.792
Friction is being neglected. Often a gravel surface is used on esacape ramps to increase friction. The rotational kinetic energy of the wheels is also being neglected.
If The Angle is 11degree then we can use inclined plane equation
a=gsin0-f/m....1
by using 1st law of motion we have:
vf=vi+at.....2
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