At standard temperature, a gas has a volume of 275mL. The temperature is then increased to 130. Celcius, and the pressure is held constant. What is the new volume?

How do I work this?

v1 = 275mL
t1 = 130. C or 403K
v2=???
t2 = ???

Can someone help me please?

The answer is 406 mL

The problem lists the gas at standard temperature which is 273 K. So T1 is 273, T2 is 403, V1 = 275 and you solve for V2. Note the correct spelling of celsius.

show working out

V2= V1T2/T1

=(0.28L)(403.15K)/(273.15K)
=0.41L

To solve this problem, you can use the combined gas law, which relates the initial and final states of a gas sample.

The combined gas law can be stated as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:
P1 and P2 are the initial and final pressures of the gas (held constant in this case)
V1 and V2 are the initial and final volumes of the gas
T1 and T2 are the initial and final temperatures of the gas

In this case, since the pressure is held constant, we can simplify the equation to:

V1 / T1 = V2 / T2

Given:
V1 = 275 mL
T1 = 130°C or 403 K

The goal is to find V2, the new volume.

Rearrange the equation to isolate V2:

V2 = (V1 * T2) / T1

Now, since we're given T2, plug in the known values to calculate the new volume V2:

V2 = (275 mL * T2) / T1

Make sure to convert the temperature from Celsius to Kelvin before substituting the values in the equation.

Remember, to convert Celsius to Kelvin, you add 273 to the Celsius value.

Once you solve for V2, you will find the new volume of the gas at the given temperature.

You know STP stands for "standard temperature & pressure." Standard T is 273 and standard P is 1 atm or 760 mm Hg.

Ahh I gotcha. So standard tempature is always 273k?

Well...Some in the world has differing standards.

http://en.wikipedia.org/wiki/Standard_conditions_for_temperature_and_pressure

you guys are a bunch of filthy cheaters