Write a chemical equation showing how each of the following species behaves as a base when dissolved in water

a.) O2-

i have

O2- + H2O --> HO2- + OH-

how do i make this right??

Without being able to write subscripts, I'm not exactly sure what O2- is; however, I'm guessing it is O=. If so, then I would write the equation as

O= + HOH ==> 2OH-

To correctly write the chemical equation showing how O2- behaves as a base when dissolved in water, you need to consider that O2- exists as the oxide ion. When the oxide ion (O2-) reacts with water (H2O), it acts as a base by accepting a proton (H+) from water. Here is the correct balanced chemical equation:

O2- + H2O → 2OH-

In this reaction, the oxide ion (O2-) gains a proton from water and forms two hydroxide ions (OH-).

To correctly write the chemical equation for how O2- behaves as a base when dissolved in water, we need to consider the reaction between O2- and water as well as the behavior of hydroxide ions (OH-) as a base.

When O2- acts as a base, it can accept a proton (H+) from water to form hydroxide ions (OH-). The balanced equation for this reaction is:

O2- + H2O → OH- + O2

However, it is important to note that hydroxide ions (OH-) are already present in water. So, the correct equation should reflect the participation of hydroxide ions as products, rather than just the O2- species. Therefore, the balanced equation should be:

O2- + H2O → OH- + O2 + OH-

This equation shows that when O2- behaves as a base, it accepts a proton from water to form hydroxide ions and releases hydroxide ions as well.