Posted by Kenny on .
What is a "Slope, Midpoint & Distance"? This is the problem:
(7,3) and (1,4)

Math 10th grade 
Damon,
slope = (Y2Y1)/(X2X1)
=(43)/17
= 7/8
=7/8
midpoint
x = X1 + (1/2)(X2X1) = 7 +(1/2)(8)
= 74
= 3
do y the same way
d^2 = (Y2Y1)^2 + (X2X1)^2
d^2 = 49+64 = 113
d = sqrt (113)