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August 31, 2014

August 31, 2014

Posted by **Kelsie** on Thursday, March 19, 2009 at 6:46pm.

4x^2-18

7x^2-847

4x^2+18

- algebra -
**drwls**, Thursday, March 19, 2009 at 7:11pm4x^2-18 = (2x + sqrt18)(2x - sqrt18)

= 4[x + (3/2)sqrt2][x - (3/2)sqrt2]

On the second one, factor out the 7 and recognize that 121 = 11^2. Ypu will have the difference of two squares.

The third one requires imaginary factors.

4x^2 + 18 = 4(x^2 + 2*9/4)

= 4[x + i(3/2)sqrt2][ x - i(3/2)sqrt2]

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