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January 27, 2015

January 27, 2015

Posted by **Chrystal** on Thursday, March 19, 2009 at 3:03pm.

a. What is the random variable?

b. The mayor of Daisy City makes $2250 a month. What percentage of Daisy City's residents has incomes that are more than the mayor?

c. Individuals with incomes of less than $1985 per monthe are exempt from city taxes. What percentage of residents is exempt from city taxes.

d. What are the minimum and the maximum incomes of the middle 95% of the residents

e. Two hundred residents have incomes of at least $4440 per month. What is the population of Daisy City.

- Quantitative Methods II -
**Damon**, Thursday, March 19, 2009 at 4:41pmYou have a normal distribution table handy. I do not so all I can do is outline the methods.

mean = 3000

sigma = 500

a. the monthly income

b. how far below mean is the mayor's income?

3000 - 2250 = 750

then how many sigmas below mean is this?

750/500 = 1.5 sigma (called "z") below mean

so now the question becomes how what percent of a normal distribution is between 1.5 sigma (called "z") below mean and + infinity

this is of course 100% - the percent between -oo and 1.5 sigma below mean

My guess not having the table handy is about 7% for between -oo and mean -1.5 sigma

so about 93 % have more income

c. 3000 - 1985 = 1015 below mean

1015/500 = 2.03 sigma below mean

look for between -oo and -2.03

This is tiny, around 2 1/2 percent if I had a table

d. middle 95% is from about F(z) = 2.5% to F(z)=97.5% or F(z) = .025 to .975

That would be from about mean -2 sigma to mean + 2 sigma (use table of z versus F(z) of course. Do not trust my guess)

so from mean -2*500 to mean + 2*500

or from $2000 to $4000

4440 - 3000 = 1440

1440/500 = 2.88 sigma above mean

so what percent below mean + 2.88 sigma?

F(z)about .995 (remember guessing

so

.005 or about .5% have incomes above 4440

.005 n = 200

n = 200/.005 = 40,000

remember I am beign very approximate guessing normal distribution table.

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