question: slove by comparison and check your solution?

a)2x-4y-5=0
3x+8y-4=0

my work so far:

2x-4y=5-------(1)
3x+8y=4-------(2)
_____________

6x-12y=15------(3) (3)-(4)
6x+16y=8-------(4)
____________________
28y/28 = 7/28

y= .25

2x-4(.25)=5
2x-1+5
2x/2 + 6/2
x = 3

ya i was wrong when i did my check, both sides werent equal, and i cant figure out why i was wrong in my work.PLEASE HELP!!!!!

you subtraced the equations wrong.

You should have gotten

6x-12y=15------(3) (3)-(4)
6x+16y=8-------(4)
____________________
-28y = 7

which leads to y=-1/4

but i divided both sides by -28 though

i did that and i got the same thing as before though?

cool .....not

To solve the system of equations using the method of comparison, you need to eliminate one variable by manipulating the equations. Here's how to do it step-by-step:

1. Multiply equation (1) by 2 and equation (2) by 3 to make the coefficients of x in both equations the same.
2(2x - 4y) = 2(5)
3(3x + 8y) = 3(4)

Simplifying these equations gives:
4x - 8y = 10 (1')
9x + 24y = 12 (2')

2. Now, you can eliminate the variable y by adding equation (1') and equation (2').
(4x - 8y) + (9x + 24y) = 10 + 12

Simplifying this equation gives:
13x + 16y = 22 (5)

3. Now, you can solve equations (5) and (4) as a system of linear equations.

13x + 16y = 22 (5)
6x + 16y = 8 (4)

Subtract equation (4) from equation (5):
(13x + 16y) - (6x + 16y) = 22 - 8

Simplifying this equation gives:
7x = 14

Divide both sides of the equation by 7 to solve for x:
x = 2

4. Now that you have the value of x, substitute it back into one of the original equations to solve for y. Let's use equation (1):

2(2) - 4y = 5
4 - 4y = 5
-4y = 1 - 4
-4y = -3

Divide both sides of the equation by -4 to solve for y:
y = 3/4 or 0.75

So, the solution to the system of equations is x = 2 and y = 0.75.

Now, to check your solution, substitute the values of x and y into both original equations and see if both sides are equal:

For equation (1):
2(2) - 4(0.75) - 5 = 0
4 - 3 - 5 = 0
-4 = 0

The left side of the equation does not equal zero. Therefore, there seems to be an error in your calculations. Double-check your steps and calculations to identify the mistake and correct it.