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January 31, 2015

January 31, 2015

Posted by **Alex** on Thursday, March 19, 2009 at 12:18pm.

Sin(x+y) + Sin(x-y) = 2sinxcosy

Okay, I've been working on the left side, and distribute, getting:

Sinx + Siny + Sinx - Siny

And, the sinx's add up to the 2sinx that I need for the right side, but the siny's cancel out if I don't change them around. So I changed one of them to 1/cscy... but I can't seem to work with that and the other siny to end up with cosy.

Where did I go wrong, or where do I go with it now?

- trig -
**Count Iblis**, Thursday, March 19, 2009 at 12:25pmSin(x+y) = Sin(x)Cos(y) + Cos(x)Sin(y)

If you replace y by minus y and add you get twice the first term, because

cos(-y) = cos(y) and sin(-y) = - sin(y).

- trig -
**Alex**, Thursday, March 19, 2009 at 2:28pmoh, dang, forgot about that identity!

Okay, well, adding that up it ends up as 2sinx2cosy... but I need it to be 2sinx(1)cosy.

or am I really tired and I'm thinking too out of the box to realize the entire term of 2sinxcosy consists of 2sinx's and 2cosy's?

if not, what do I switch up to drop a cosy to satisfy the right side of the equation? oh man, am i sure forgetting everything about math, lol.

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