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April 18, 2015

April 18, 2015

Posted by **Carline** on Thursday, March 19, 2009 at 11:19am.

- Statistics/probability -
**PsyDAG**, Thursday, March 19, 2009 at 11:27amAssuming that the 60 and 50 are studying only one language, there cannot be 20 studying both out of 120 students. Do you have your total number of students wrong?

Repost with correct data. Thanks for asking.

- Statistics/probability -
**Reiny**, Thursday, March 19, 2009 at 11:41amP(F or L) =P(F) + P(L) - P(F and L)

= 60/120 + 50/120 - 20/120

= 90/120

= 3/4

or you could make Venn diagrams showing overlapping circles for French and Latin within a universal set of 120

enter 20 in the intersection of the two circles.

then 40 would go in the non-overlapping part of French and 30 in the non-overlapping part of Latin

total of inside of both circles = 40+20+30 = 90

So Prob of F or L is 90/120 = 3/4

for b) number of students outside the two circles is 120-90 = 30

so Prob of neither F or L is 30/120 = 1/4

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