how mant moles are in 1.30g of (NH4)2SO4?
answer in units of mol.
today our teacher briefly went over this and doing my homework i totally lost it. and cant remember for the life of me what to do could you please help me and show me step by step what to do.
thanks
determine the mole mass of ammonium sulfate.
add the atomic masses of each of the constituents.
Constiutents are 2N, 8H, 1S, 4O
look up the atomic masses of N, H, S, and O, and then multiply each by the coefficent. I get a little over 132grams. YOu do it accurately.
Then finally, divide that into 1.30grams
Of course! I'll be happy to help you step by step.
To determine the number of moles in a given mass of a substance, we need to use the formula:
Number of moles = Mass (g) / Molar mass (g/mol)
Step 1: Find the molar mass of (NH4)2SO4.
The molar mass is the sum of the atomic masses of all the atoms in a molecule. Let's calculate it:
(NH4)2SO4 consists of:
2 ammonium ions (NH4+) with a molar mass of NH4+ = Atomic mass (N) + 4 * Atomic mass (H)
1 sulfate ion (SO4^2-) with a molar mass of SO4^2- = Atomic mass (S) + 4 * Atomic mass (O)
You can find the atomic masses of nitrogen (N), hydrogen (H), sulfur (S), and oxygen (O) on the periodic table.
Step 2: Add up the molar masses of all the atoms in (NH4)2SO4 to get the molar mass of the compound.
Step 3: Substitute the given mass (1.30g) and the molar mass into the formula:
Number of moles = 1.30g / Molar mass
Step 4: Calculate the value.
Now, let's go ahead and calculate the number of moles in 1.30g of (NH4)2SO4. However, I'll need the molar masses of the individual atoms to proceed.