A 15 N wooden block is dragged for 15 meters across a wooden floor in 15 seconds...

I'm given that the mew (the greek leter uk) or however u say it is .2

I have to make a free body diagram

I sloved and got
Fn = 15 N
mg = -15 N
Ff = -3 N

How do I solve for the force applied to get the force opposite Ff. It has to be greater than 3 N sense the block moved across the floor but how do I know the net force? I need to know the force applied which I don't know and have to solve for and don't know how to...

The quetion then asks me how much work was performed and covert to horsepower which i think I can do once I have the net force but I don't know how to get the net force without the force applied. I'm given no angle or anthing at which the force was applied either...

If it was dragged at constant velocity, then you are right with Ff=3N (note, not negative). Net force is the accelerating force, above the friction force. If it were at constant velocity, you have no idea what net force is. With constant veloicty, net force is zero (it is not accelerating).

Work performed: Ff*distance

how do I solve for accelerating force above friction force?

To solve for the force applied, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, since the block is moving at a constant velocity, there is no acceleration, and therefore the net force is zero.

Since the force of friction (Ff) is acting in the opposite direction to the applied force, the net force equation becomes:

Net force = Applied force - Force of friction = 0

Therefore, the applied force is equal to the force of friction:

Applied force = Force of friction = 3 N

Now, to calculate the work performed, you can use the formula:

Work = Force * Distance * cos(θ)

In this case, the force used to calculate work is the applied force (3 N), the distance is 15 meters, and the angle (θ) is not given, which means it is most likely 0 degrees (indicating that the force is applied parallel to the floor). In this case, cos(0) equals 1, so the formula simplifies to:

Work = Applied force * Distance

Plugging in the values, we get:

Work = 3 N * 15 m = 45 J (Joules)

To convert the work to horsepower, you can use the conversion factor:

1 horsepower (hp) = 746 Watts (W)

To convert from Joules to Watts, divide the work by the time taken (15 seconds):

Power = Work / Time

Power = 45 J / 15 s = 3 W (Watts)

Finally, to convert from Watts to horsepower, divide the power by 746:

Horsepower = Power / 746

Horsepower = 3 W / 746 = 0.004 hp (approximately)

So, the work performed is 45 Joules and is equivalent to approximately 0.004 horsepower.