Posted by Janet on Wednesday, March 18, 2009 at 7:53pm.
the area of the first square is 1
clearly each successive square is 1/2 of the previous one.
check: side of second square:
(1/2)^2 + (1/2)^2 = x^
x^2 = 1/2
x = 1/√2
so the area = (1/√2)^2 = 1/2
so we have an infinite series
1 + 1/2 + 1/4 + ...
a=1, r=1/2
S∞ = 1/(1-r) = 1/(1-1/2) = 2
hint for b)
side of first square = 1
side of second square = 1/√2
....
take it from there.
so the perimeter is four and the series stay the same?
Huh?
the perimeter of the first square =4
the perimeter of the second square = 4*(1/√2) = 4/√2
so a=4, r = 1/√2
sum = 4/(1 - 1/√2)
=
you finish it , ok?
yeah that is what I was asking...thanx.!
Related Questions
calculus - Consider the infinite series of the form: (+/-)3(+/-)1(+/-)(1/3...
calculus - Consider the infinite series of the form: (+/-)3(+/-)1(+/-)(1/3...
Calculus - Consider the infinite series of the form: (+/-)3(+/-)1(+/-)(1/3...
Math 12A - Each side of a square is 20cm. Four points on the sides are joined as...
physics - so i have a circuit (series) where the the emf=12 V and R1=2 ohms and ...
circuits - so i have a circuit (series) where the the emf=12 V and R1=2 ohms and...
Excel Help - 3) __________ are used to compare sets of data in one chart. Time ...
calculus - state the power series of an appropriate familiar function and use it...
geometry - The coordinates of triangle ABC areA(0,0), B(2,6), and C(4,2). Using ...
geometry - The coordinates of triangle ABC areA(0,0), B(2,6), and C(4,2). Using ...
For Further Reading