Posted by Harold on Monday, March 16, 2009 at 11:48pm.
Use conservation of energy. The loss of gravitational potential energy will equal the potential energy stored in the spring.
0.05 kg * 9.8 m/s^2 * 2 meters = (1/2) k X^2
X^2 = 0.014m^2
X = 0.12 m
I have neglected the gravitational potential energy change during the small spring compression . To include that effect, I would have to know the ramp angle
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