Posted by lt on .
How do I solve:
log6 (x^25x) = 1
1/2log5(r2)log5 r)
log2 (x1/x^8)
I really don't know how to do these or even start

Math (#1 of 3) 
drwls,
I assume the number immediately after log is the base of the log.
log6 (x^25x) = 1 is equivalent to writing
6^1 = x^25x = 6
Rewrite as a polynomial
x^2 5x 6 = 0
(x6)(x+1) = 0
x = 6 or 1
Do the others the same way. Rewrite the equation containing the log term as a polynomial, and factor it.