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September 18, 2014

September 18, 2014

Posted by **lt** on Monday, March 16, 2009 at 8:47pm.

log6 (x^2-5x) = 1

1/2log5(r-2)-log5 r)

log2 (x-1/x^8)

I really dont know how to do these or even start

- Math (#1 of 3) -
**drwls**, Tuesday, March 17, 2009 at 9:15amI assume the number immediately after log is the base of the log.

log6 (x^2-5x) = 1 is equivalent to writing

6^1 = x^2-5x = 6

Rewrite as a polynomial

x^2 -5x -6 = 0

(x-6)(x+1) = 0

x = 6 or -1

Do the others the same way. Rewrite the equation containing the log term as a polynomial, and factor it.

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