Two angles are complementary. The sum of the measure of the first angle and one-fourth of the second angle is 69 degrees. Find the measures of the angles.

What is the measure of the smaller angle?
What is the measure of the other angle?

Can somebody help me set this up?
PLEASE!!!!!!

Let one angle be A and the other angle be B. Since they are complimentary,

A + B = 90 (degrees)
They also tell you that
A + B/4 = 69
Therefore (subtracting one equation from the other)
3/4 B = 21
B = (4/3)*21 = 28
A = 62

Sure, I can help you set up the problem. Let's call the first angle "A" and the second angle "B".

Since the two angles are complementary, we know that the sum of their measures is 90 degrees. So we can write the equation:

A + B = 90 (equation 1)

We are also given that the sum of the first angle and one-fourth of the second angle is 69 degrees. This can be written as the equation:

A + (1/4)B = 69 (equation 2)

Now we have a system of two equations. To solve for the measures of the angles, we can use the method of substitution or elimination.

For substitution, we can solve equation 1 for A and substitute it into equation 2:

A = 90 - B

Now, substitute this expression for A in equation 2:

(90 - B) + (1/4)B = 69

Simplify the equation:

90 - B + (1/4)B = 69

Now, solve for B:

(1/4)B - B = 69 - 90

Combine like terms:

(-3/4)B = -21

Multiply both sides by (-4/3) to isolate B:

B = (-21) * (-4/3)

B = 28

Now that we have found B, substitute this value back into equation 1 to find A:

A + 28 = 90

A = 90 - 28

A = 62

Therefore, the measure of the smaller angle (A) is 62 degrees, and the measure of the other angle (B) is 28 degrees.