Calc
posted by Vince on .
Air is being pumped into a spherical balloon so that its volume increases at a rate of 90{cm}^3/s. How fast is the surface area of the balloon increasing when its radius is 7{cm}? Recall that a ball of radius r has volume \displaystyle V={4}/{3}pie r^3 and surface area S=4\pi r^2

dV/dt= 4/3 PI 3 r^2 dr/dt
solve for dr/dt given dv/dt
Then dS/dt=4PI 2r dr/dt, knowing dr/dt solve for dS/dt
and it is done. 
ok thanks alot for clearing it up