Let the smaller number be x; that means the other number must be 2x + 8.
Solve the equation
x(2x+8) = 2x + 8 + x + 8
which can also be written
2x^2 + 8x = 3x + 16
2x^2 + 5x -16 = 0
There seems to be no integer solution. The smaller number is
x = (-5 + sqrt 153)/4 = 1.84233
and the larger number is 2x + 1 = 11.68466
Their sum is 13.5267
and the product is 21.527
drwls, you made a slight mistake - you forgot a factor of 2 in the RHS of the equation.
If N1 = x and N2 = 2x + 8
then the equation is
x(2x+8) = 8 + 2*(2x + 8 + x)
Which simplifies to
x^2 - x - 12 = 0
which has two integer solutions.
Hope that helps!
algebra - One number is 10 more than twice another.Their product is 10 more ...
algebra - Five times the smallest of three consecutive odd integers is ten more ...
Algebra 1- Math - The sum of a smaller number and twice a larger number is 67. ...
Math - The sum of two numbers is twice their difference. The larger number is 6 ...
Math - 1)one number is four more than a second number. Twice the second is three...
Math - one postive number is 9 more than twice a number if product is 893 find ...
math - The sum of two numbers is 25. Twelve less than four times one of the ...
math - One number is eight more than twice another. If their sum is decreased by...
Grade 8 Math - Can you write them in Mathematical/numbers form I'll solve them ...
math help - four more than seven times y = ? Eights less than seven-eights of w...