I've been having problems with solving equations that involve fractions with the following problem can I get some help for solving equations that involve fractions?

x+1=2/3x

Thanks for the help.

I will assume that 2/3x is (2/3)x and not 2/(3x). As you have written it, it could be either. They are NOT the same.

Subtract x from both sides of the equation. This leaves you with
-1/3 x = 1

Multiply both sides by -3 for the final answer.
x = -3

Of course, I'd be happy to help you solve the equation involving fractions. To solve equations with fractions, we need to eliminate the denominators first.

In the given equation, we have a fraction on the right side (2/3x). To eliminate the denominator of this fraction, we need to multiply both sides of the equation by the least common denominator (LCD) of the fractions involved.

To find the LCD, we need to determine the least common multiple (LCM) of the denominator(s). In this case, the denominator of the fraction is 3. Since there are no other denominators, the LCM of 3 is simply 3.

Now, let's multiply both sides of the equation by 3 to eliminate the fraction:

3(x + 1) = 3 * (2/3x)

This simplifies to:

3x + 3 = 2x

Next, we can isolate the variable x by moving all terms containing x to one side of the equation. Let's subtract 2x from both sides:

3x - 2x + 3 = 2x - 2x

Simplifying further, we get:

x + 3 = 0

Finally, we can isolate x by moving the constant term to the other side of the equation. In this case, let's subtract 3 from both sides:

x + 3 - 3 = 0 - 3

Simplifying, we find:

x = -3

Therefore, the solution to the equation x + 1 = (2/3)x is x = -3.