Posted by mkcolema on Friday, March 13, 2009 at 8:56pm.
f(x)=(5x4)e^2x
How do you find the one critical number??

mathcalc  GanonTEK, Friday, March 13, 2009 at 9:15pm
Differentiate and put equal to zero.
f'[x] = 5e^(2x) + 2e^(2x)(4+5x)
f'[0] = 3
So the xcoordinate is 3
I'd guess that that is what the question wants.
Hope that helps

mathcalc  GanonTEK, Friday, March 13, 2009 at 9:23pm
I made a slight error. i don't want f'[0], i want f'[x] = 0 to find x = something.
so we get 5e^(2x) + 2e^(2x)(4+5x) = 0
divide across by e^(2x)
we get 5 + 2(4+5x) = 0
5  8 + 10x =0
10x = 3
x = 3/10
Sorry about the mistake in my first post.
hope that helps
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