Wednesday

August 20, 2014

August 20, 2014

Posted by **mkcolema** on Friday, March 13, 2009 at 8:41pm.

f(x)=x^7(x+2)^2

On which two intervals is the function increasing (enter intervals in ascending order)?

Find the region in which the function is positive

Where does the function achieve its minimum?

- math-calc -
**GanonTEK**, Friday, March 13, 2009 at 9:55pmit's turning points are when

[1] x*7 = 0 or x = 0

[2] (x+2)^2 = 0 or x - -2

The graph is increasing when

(-12 to -2) and (0 to 10)

To work this out find the turning points by finding f'[x]=0

ok hope that helps

**Related Questions**

Math - For x [–14,13] the function f is defined by f(x)=(x^3)(x+6)^4 On which ...

calculus - For x ∈ [−12, 10] the function f is defined by f(x) = x7(...

calculus - For x including [–15, 13] the function f is defined by f(x)=x^7(x+4)^...

CALCULUs - For all x in the interval [-11,13] the function f is defined by x^3(x...

math-calc - Consider the function f(x)= (2x+8)/(6x+3). For this function there ...

calculus - f(x)= x^3/x^2-16 defined on the interval [-19,16]. Enter points, such...

Calc - f(x) = x^2 / (x - 7)^2 (a) Find the vertical and horizontal asymptotes. x...

math - . Given the following function, f(x)=-x^2 -8x find: (a) vertex, (b) axis...

algebra - Given the following function, find: (a) vertex (b) axis of symmetry (c...

Calc - Let F be the function defined by F(X)=12X to the 2/3 power minus 4X Find ...