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September 18, 2014

September 18, 2014

Posted by **Joshua** on Friday, March 13, 2009 at 2:20pm.

1.rcos(theta)=1

x=1

2.r=2*sin(theta)+2*cos(theta)

r^2=2rsin(theta)+2rcos(theta)

x^2+y^2=2y+2x (a little unsure what do next if this is correct)

3.r=tan(theta)sec(theta)

r=sin(theta)/(cos(theta))^2

r(cos(theta))^2=sin(theta)

r^2(cos(theta))^2=rsin(theta)

x^2=y

- Calculus -
**Reiny**, Friday, March 13, 2009 at 5:44pmI agree with your answers

Nice work on #3

in #2, form

x^2 + y^2 = 2y + 2x you have a circle

you could complete the square, and find its centre and radius in this way ...

x^2 + y^2 - 2y - 2x = 0

x^2 - 2x + 1 + y^2 - 2y + 1 = 2

(x-1)^2 + (y-1)^2 = 2

so centre is (1,1) and radius is √2

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