Posted by Joshua on Friday, March 13, 2009 at 2:20pm.
I wanted to confirm that I solved these problems correctly (we had to convert the polar curves to Cartesian equations).
1.rcos(theta)=1
x=1
2.r=2*sin(theta)+2*cos(theta)
r^2=2rsin(theta)+2rcos(theta)
x^2+y^2=2y+2x (a little unsure what do next if this is correct)
3.r=tan(theta)sec(theta)
r=sin(theta)/(cos(theta))^2
r(cos(theta))^2=sin(theta)
r^2(cos(theta))^2=rsin(theta)
x^2=y

Calculus  Reiny, Friday, March 13, 2009 at 5:44pm
I agree with your answers
Nice work on #3
in #2, form
x^2 + y^2 = 2y + 2x you have a circle
you could complete the square, and find its centre and radius in this way ...
x^2 + y^2  2y  2x = 0
x^2  2x + 1 + y^2  2y + 1 = 2
(x1)^2 + (y1)^2 = 2
so centre is (1,1) and radius is √2
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