physics
posted by physics on .
find the final equilibirum temperature when 10.0 g of milk at 10.0degC is added to 1.60*10^2 g of coffee with a temperatrure of 90.0degC. Assume the specific heats of coffee and milk are the same as for water (Cp,w=4.19J/g*degC) and disregard the heat capacity of the container
massmilk*cmilk*(Tf10)+masscoffee(ccoffee)(Tf90)=0
please show me in simple steps how to solve for Tf
thanks a lot

massmilk*cmilk*(Tf10)+masscoffee(ccoffee)(Tf90)=0
divide through by specific heat, it goes away.
10*(Tf10)+160(Tf90)=0
Tf(10+160)100160*90=0
Tf= (14400/170) 
so Tf is 84.70?