Posted by Angela on .
consider the following sample statistics from a population that is aproximatly normal. n=15, s= 7.92,level of confidence is 99 %
Calculate the margin of error( round to the nearest hunderth)
Margin of error = + or - (z-value)(s/√n)
...where z-value is found using a z-table for 99% confidence, s = standard deviation, and n = sample size.
Look up the value in the table, then substitute what you know into the formula.
I hope this will help get you started.