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February 1, 2015

February 1, 2015

Posted by **Jaisa** on Wednesday, March 11, 2009 at 1:53am.

- Science -
**drwls**, Wednesday, March 11, 2009 at 11:08amYou are given enough information to solve for the takeoff velocity, "hang time" and "launch angle", but I could find no real solution for the hang time, using your inputs.

- Science -
**drwls**, Wednesday, March 11, 2009 at 1:16pmHer mass is M = Weight/g = 51.0 kg

Her initial velocity, from her initial kinetic energy E (equal to work done), is

Vo = sqrt(2 E/M) = 3.13 m/s

The horizontal distance X that she travels is related to her "takeoff angle" A by the equation

X = 2.5 = (Vo^2/g)*sin(2A)

which leads to

2.5 = 1.00 sin (2A)

There is no angle 2A (or A) that satifies this equation. She does not have enough initial kinetic energy to jump that far. You may have copied something wrong

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