Posted by **bill nye** on Tuesday, March 10, 2009 at 5:11pm.

Consider the function f(x) whose second derivative is f(x)=9x+6sin(x). If f(0)=4 and f(0)=3, what is f(x)? Please do not include the constant (+C) in your answer.

- calculus -
**drwls**, Tuesday, March 10, 2009 at 7:44pm
You wrote << f(0)=4 and f(0)=3,>> but

both cannot be true. One of the f(x) functions must be the derivative, f'(x). Which is it?

Anyway, all you have to do is integrate your f''(x) once and use the value of f'(x) at x=0 to get the first cosntant, and then integrate it again and use the value of f(0)at x=0 to get the second constant

- calculus -
**bill nye**, Tuesday, March 10, 2009 at 8:03pm
oh im sorry it is f(0)=4 and f'(0)=3

- calculus -
**bill nye**, Tuesday, March 10, 2009 at 8:29pm
and it's f''(x)=9x+6sin(x)

sorry

- calculus -
**bill nye**, Thursday, March 12, 2009 at 12:29am
i got the answer 1.5x^3-6sinx+9x+4

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