Posted by bill nye on .
Consider the function f(x) whose second derivative is f(x)=9x+6sin(x). If f(0)=4 and f(0)=3, what is f(x)? Please do not include the constant (+C) in your answer.

calculus 
drwls,
You wrote << f(0)=4 and f(0)=3,>> but
both cannot be true. One of the f(x) functions must be the derivative, f'(x). Which is it?
Anyway, all you have to do is integrate your f''(x) once and use the value of f'(x) at x=0 to get the first cosntant, and then integrate it again and use the value of f(0)at x=0 to get the second constant 
calculus 
bill nye,
oh im sorry it is f(0)=4 and f'(0)=3

calculus 
bill nye,
and it's f''(x)=9x+6sin(x)
sorry 
calculus 
bill nye,
i got the answer 1.5x^36sinx+9x+4