solid mensuration
posted by ylzik on .
is what i've been doing correct so far:
find the value of h for a spherical segment whose volume is equivalent to 159pi if the radii of the bases are 5m and 4m respectively
v= (pi/6)(3a^2 + 3b^2 + h^2) h
v= 0.52 ((3)(5^2) + (3)(4^2) + h^2) h
= 0.52 ((3)(25) + (3)(16) + h^2) h
= 0.52 (75 + 48 + h^2) h
=(39 + 24.96 + 0.52h^2) h
=(63.96 + 0.52h^2) h
if so, how do i find the value of h?
if not, where did i go wrong?
thank youuuuu so much for any help!!!

looks like you are using
V = (Pi/6)(3r1^2+3r2^2+h^2)h
where r1 and r2 are the two radii
but you are given that the volume is 159pi
159pi = pi/6(75 + 48 + h^2)h
954 = 123h + h^3
h^3 + 123h  954 = 0
this solves for h = 6 and 2 complex roots.