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November 27, 2014

November 27, 2014

Posted by **Dippy** on Sunday, March 8, 2009 at 7:49pm.

Is there some sort of equation to use to solve this? And how can the square of an interger actually be 30 more than the integer? I am confused!

- ALGEBRA 1 -
**Count Iblis**, Sunday, March 8, 2009 at 8:53pmThis means that if x is the integer, we have:

x^2 = x + 30 -->

x^2 - x - 30 = 0 --->

(x-6)(x+5)= 0 -->

x = 6 or x = -5

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