The square of an integer is 30 more than the integer. Find the integer.
Is there some sort of equation to use to solve this? And how can the square of an interger actually be 30 more than the integer? I am confused!
ALGEBRA 1 - Count Iblis, Sunday, March 8, 2009 at 8:53pm
This means that if x is the integer, we have:
x^2 = x + 30 -->
x^2 - x - 30 = 0 --->
(x-6)(x+5)= 0 -->
x = 6 or x = -5