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A 50.0 mL sample of 0.51 M benzoic acid, C6H5COOH, a weak monoprotic acid, is titrated with 0.40 M NaOH. Calculate the pH at the equivalence point. Ka of C6H5COOH = 6.5 10-5.

what am i supposed to do with this?

  • Chemistry -

    The pH at the equivalence point is determined by the hydrolysis of the salt, in this case, sodium benzoate.
    C6H5COO^- + HOH ==>C6H5COOH + OH^-

    Now, write the Keq expression, set up an ICE chart, and solve for OH^-. Then change to pOH, then to pH. Post your work if you get stuck. Kb for the base (the C6H5COO^-) is Kw/Ka.

  • Chemistry -

    Idek hehe

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