Posted by **Joe** on Sunday, March 8, 2009 at 2:09pm.

scott and laura have both invested some money. Scott invested $3,000 more then laura and at a 2% higher interest rate. If scott received $800 annual interest and laura received $400, how much did scott invest?

- investment question -
**drwls**, Sunday, March 8, 2009 at 3:47pm
Let their investments be L (Laura) and S (Scott). Laura's annual interest rate is I (expressed as a decimal) and Scott's is I + 0.02

S = L + 3000

800 = S*(I + 0.02)

400 = L I

You have three equations in three unknowns, which is enough to solve for all of them.

800 =(L+300)(I+0.02)

800 = LI + 300I +0.02L + 6

= 400 + 300I + 0.02L+ 6

= 400 + 300*400/L + 0.02L + 6

= 406 + 120000/L +0.02L

This can be turned into a quadratic equation for L. Take the positive root.

- investment question -
**Anonymous**, Thursday, February 2, 2012 at 10:09pm
Actually, you should take the negative root. You should plug both answers into the original equation to see which one fits. The one that makes sense (i.e. 800=800) should be the correct one.

Don't forget that Scott invested 3,000 more than Sally (S = L + 3000). You just solved for L. The question is asking for what S is. You're not done yet.

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